Question
Construct an isosceles triangle in which: $AB = AC, BC = 6 \ cm$ and $\angle B = 75^\circ $
✓
Answer
In $\triangle ABC,$
$AB = AC ....($given$)$
$\Rightarrow \angle ACB = \angle ABC = 75^\circ $
Steps:
$1.$ Draw $BC = 6\ cm.$
$2$. Construct angle $\angle BCM = 75^\circ $ and $\angle CBN = 75^\circ $
$3.$ Ray $CM$ and ray $BN$ meets at $A.$
Thus, $\text{ABC}$ is required angle.
$AB = AC ....($given$)$
$\Rightarrow \angle ACB = \angle ABC = 75^\circ $
Steps:
$1.$ Draw $BC = 6\ cm.$
$2$. Construct angle $\angle BCM = 75^\circ $ and $\angle CBN = 75^\circ $
$3.$ Ray $CM$ and ray $BN$ meets at $A.$
Thus, $\text{ABC}$ is required angle.
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