Question
Convert 1-bromopropane to 2-bromopropane.

Answer

$\text{CH}_3\text{CH}_2\text{CH}_2\text{Br}\xrightarrow{\text{KOH(alc)}}\text{CH}_3-\text{CH}=\text{CH}_2\\ \ \ \ _{1-\text{bromopropane}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{Propene}}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\xrightarrow[\text{Markownikoff addition}]{\text{HBr}}\text{CH}_3-\text{CH}-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{2-\text{bromopropane}}$

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