MCQ
Coordinates of centre and radius of the circle $(x-3)^2+(y+4)^2=25$ are respectively:
 
  • A
    $(3,4), 25$
  • B
    $(-3,4), 5$
  • $(3,-4), 5$
  • D
    $(3,-4), 25$

Answer

Correct option: C.
$(3,-4), 5$
  1. $(3, -4), 5$
Solution:
$=(x-3)^2+(y+4)^2=25$
$=(x-3)^2+(y-(-4))^2-(5)^2$
$=(x-4)^2+(y-k)^2-(r)^2$
$=r=5(h, k)=(3,-4)$

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