Correct order of second ionization enthalpy are : - Vidyadip

MCQ

Correct order of second ionization enthalpy are :

A
$Sc < V < Cr < Ti$
B
$V < Sc < Cr < Ti$
C
$Sc < Cr < V < Ti$
✓
$Sc < Ti < V < Cr$

✓

Answer

Correct option: D.

$Sc < Ti < V < Cr$

(D) $Sc < Ti < V < Cr$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "SECTION - A [CHEMISTY - MCQ]" from Model Paper 1→Model Paper 1 — all question types→NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Total number of $d$ electrons present an element with atomic no. $78$ is

Nitrous oxide is known as

An aqueous solution freezes at $-\,2.55\,^oC$. ........ $^oC$ is its boiling point .
$[ K_b(H_2O) = 0.52\, K \,Kg\, mol^{-1},K_f (H_2O) = 1.86 \,K \,Kg\, mol^{-1} ]$

Compare the carbon-carbon $\sigma $ bond length in ethane, ethylene and acetylene ?

A completely filled $d$-orbital $({d^{10}})$

For the reaction system $2NO(g) + {O_2}(g) \to 2N{O_2}(g)$ volume is suddenly produced to half its value by increasing the pressure on it. If the reaction is of first order with respect to $O_2$ and second order with respect to $NO,$ the rate of reaction will

Identify the product $D$ in the following series of reaction

$C{H_3}COOH\xrightarrow{{LiAl{H_4}}}A\mathop {\xrightarrow{{{H^ + }}}}\limits_{443\,K} B\xrightarrow{{B{r_2}}}C\mathop {\xrightarrow{{alc.}}}\limits_{KOH} D$

Rectified spirit obtained by fermentation contains $4.5$ $\%$ of water. So in order to remove it, rectified spirit is mixed with suitable quantity of benzene and heated. Benzene helps because

Assertion : For an isothermal reversible process $Q = -W$ i.e. work done by the system equals the heat absorbed by the system.
Reason : Enthalpy change $(\Delta H)$ is zero for isothermal process.