MCQ
${\cos ^{ - 1}}\frac{1}{2} + 2{\sin ^{ - 1}}\frac{1}{2}$ is equal to
  • A
    $\frac{\pi }{4}$
  • B
    $\frac{\pi }{6}$
  • C
    $\frac{\pi }{3}$
  • $\frac{{2\pi }}{3}$

Answer

Correct option: D.
$\frac{{2\pi }}{3}$
d
(d) ${\cos ^{ - 1}}\frac{1}{2} + 2{\sin ^{ - 1}}\frac{1}{2} $

$= \frac{\pi }{3} + \frac{{2\pi }}{6} = \frac{{2\pi }}{3}$.

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