MCQ
${\cos ^{ - 1}}\frac{1}{2} + 2{\sin ^{ - 1}}\frac{1}{2}$ is equal to
- A$\frac{\pi }{4}$
- B$\frac{\pi }{6}$
- C$\frac{\pi }{3}$
- ✓$\frac{{2\pi }}{3}$
$= \frac{\pi }{3} + \frac{{2\pi }}{6} = \frac{{2\pi }}{3}$.
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