Question
$\cos^{-1} \left(\cos \frac{7 \pi}{6}\right)$ बराबर है

Answer

$\cos ^{-1}\left(\cos \frac{7 \pi}{6}\right) = \cos ^{-1}\left[\cos \left(2 \pi-\frac{5 \pi}{6}\right)\right]$
जहाँ, $\frac{5 \pi}{6} \in[0, \pi]
\therefore \cos^{-1} \left(\cos \frac{7 \pi}{6}\right) $
$= \cos^{-1} \left[\cos \left(\frac{5 \pi}{6}\right)\right]=\frac{5 \pi}{6} [\because \cos (2 \pi-\theta)=\cos \theta]$
 

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