MCQ
$\cos 15^\circ - \sin 15^\circ = . . .$
- ✓$\frac{1}{{\sqrt 2 }}$
- B$\frac{1}{2}$
- C$ - \frac{1}{{\sqrt 2 }}$
- D$0$
$= \sqrt 2 \,.\,\cos \,\,{60^o}$
$ = \sqrt 2 \,.\frac{1}{2} = \frac{1}{{\sqrt 2 }}$.
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