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Inverse Trigonometric Functions — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSInverse Trigonometric Functions1 Mark
Question
$\cos ^{-1}\left(\frac{1}{2}\right)+2 \sin ^{-1}\left(\frac{1}{2}\right)+4 \tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)$ is equal to
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Answer

(c) : $\cos ^{-1}\left(\frac{1}{2}\right)+2 \sin ^{-1}\left(\frac{1}{2}\right)+4 \tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)$
$
=\frac{\pi}{3}+2 \cdot \frac{\pi}{6}+4 \cdot \frac{\pi}{6}=\frac{\pi}{3}+\frac{\pi}{3}+\frac{2 \pi}{3}=\frac{4 \pi}{3}
$

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