MCQ
${\cos ^2}\left( {\frac{\pi }{4} - \beta } \right) - {\sin ^2}\left( {\alpha - \frac{\pi }{4}} \right) = $
  • A
    $\sin (\alpha + \beta )\sin (\alpha - \beta )$
  • B
    $\cos (\alpha + \beta )\cos (\alpha - \beta )$
  • C
    $\sin (\alpha - \beta )\cos (\alpha + \beta )$
  • $\sin (\alpha + \beta )\cos (\alpha - \beta )$

Answer

Correct option: D.
$\sin (\alpha + \beta )\cos (\alpha - \beta )$
d
(d) ${\cos ^2}\left( {\frac{\pi }{4} - \beta } \right) - {\sin ^2}\left( {\alpha - \frac{\pi }{4}} \right)$

$ = \cos \,\left( {\frac{\pi }{4} - \beta + \alpha - \frac{\pi }{4}} \right)\,\cos \,\left( {\frac{\pi }{4} - \beta - \alpha + \frac{\pi }{4}} \right)\,$

$ = \cos (\alpha - \beta )\cos \left( {\frac{\pi }{2} - \overline {\alpha + \beta } } \right) $

$= \cos (\alpha - \beta )\sin (\alpha + \beta )$.

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