Question
${\cot ^{ - 1}}3 + {\rm{cose}}{{\rm{c}}^{ - 1}}\sqrt 5 =$
$ = {\cot ^{ - 1}}\left( {\frac{{3 \times 2 - 1}}{{3 + 2}}} \right) = {\cot ^{ - 1}}(1) = \frac{\pi }{4}$.
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