\(\mathrm{Cu}^{2 \mathrm{+}}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cu} \quad 0.34 \quad=-2 \mathrm{F}(0.34)\)
\(\mathrm{Cu}^{+}+\mathrm{e}^{-} \longrightarrow \mathrm{Cu} \quad \quad 0.522 \quad=-\mathrm{F}(0.522)\)
\(\mathrm{Cu}^{2 \mathrm{+}}+\mathrm{e}^{-} \longrightarrow \mathrm{Cu}^{+}\)
\(\Delta \mathrm{G}^{0}=-2 \mathrm{F}(0.34)-(-\mathrm{F}(0.522))\)\(=-\mathrm{F}(0.68-0.522)=-F(0.158)\)
\(\mathrm{E}^{0}=\frac{-\mathrm{F}(0.158)}{-\mathrm{F}}=0.158 \mathrm{V}\)
$\Delta G_{f}^{o}\left(A g_{2} O\right)=-11.21\, kJ\,mol ^{-1}$
$\Delta G_{f}^{o}(Z n O)=-318.3\, kJ \,mol ^{-1}$
ત્યારે $E^{o}$કોષ નો બટન શેલ.........$V$ શું હશે ?
($Cu$નું આણ્વિય દળ $63.5\, amu$)