\(\because \,\,C{u^{ + 2}}\, + \,\,{e^ - }\, \to \,\,C{u^ + }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{E^ o }\, = \,\, \,\,0.153\,\,volt\)
\(\therefore \,\,C{u^ + }\, \to \,\,C{u^{ + 2}}\, + \,\,{e^ - }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,E_2^o \,= \,- \,0.153\,volt,\,\,{n_2}\, = \,1\)
\(C{u^ + }\, + \,\,{e^ - }\, \to \,\,Cu\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,E_3^o \,\, = \,\,??,\,\,{n_3}\, = \,\,1\)
\(\therefore \,{\mkern 1mu} {\mkern 1mu} E_3^o{\mkern 1mu} {\mkern 1mu} = \frac{{{\mkern 1mu} {n_1}E_1^o{\mkern 1mu} + {\mkern 1mu} {\mkern 1mu} {n_2}E_2^o}}{{{n_3}}}\)
\( = \,\,\frac{{2\,\, \times \,\,0.337\,\, + \,\,1\,\, \times \,\,( - 0.153)}}{1}\)
\( = \,\,\,0.521\,\,volt\)
$Ag$ , $Ni$ , $Cr$
$6 {OH}^{-}+{Cl}^{-} \rightarrow {ClO}_{3}^{-}+3 {H}_{2} {O}+6 {e}^{-}$
પોટેશિયમ ક્લોરેટ $10.0\, {~g}$ પેદા કરવા માટે $x\, A$નો પ્રવાહ $10\, h$ માટે પસાર કરવો પડે છે. ${x}$નું મૂલ્ય $.......$ છે. (નજીકના પૂર્ણાંકમાં)
(આણ્વિય દળ $\left.{KClO}_{3}=122.6 {~g} {~mol}^{-1}, {~F}=96500 {C}\right)$
વિદ્યુતવિભાજય $X$ શું છે?
