$mol^{-1}, ᴧ^{0}\, KCl = 150\, S\, cm^{2}\, mol^{-1}$ હોય, તો $ᴧ^{0}\, NaBr$ .............. ${\rm{S}}\,{\rm{c}}{{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$ શોધો.
$[Fe(CN)_6]^{4-} \rightarrow [Fe(CN)_6]^{3-} + e^{-1}\, ;$ $ E^o = -0.35\, V$
$Fe^{2+} \rightarrow Fe^{3+} + e^{-1}\ ;$ $E^o = -0.77\, V$