MCQ
$[Cu(CN)_4]^{2-}$ is more stable than $[Cu(NH_3)_4]^{2+}$ because :-
  • A
    stability constant of $[Cu(CN)_4]^{2-}$ is greater than $[Cu(NH_3)_4]^{2+}$
  • B
    $CN^-$ is stronger ligand than $NH_3$
  • both $(A)\, \& \,(B)$
  • D
    none

Answer

Correct option: C.
both $(A)\, \& \,(B)$
c

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$\mathrm{I}_2+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{I}\ \ \   \mathrm{E}^{\circ}=0.54 $

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$(A)$ Chloride ion is oxidized by $\mathrm{O}_2$

$(B)$ $\mathrm{Fe}^{2+}$ is oxidized by iodine

$(C)$ Iodide ion is oxidized by chlorine

$(D)$ $\mathrm{Mn}^{2+}$ is oxidized by chlorine

$2.$ While $\mathrm{Fe}^{3+}$ is stable, $\mathrm{Mn}^{3+}$ is not stable in acid solution because

$(A)$ $\mathrm{O}_2$ oxidises $\mathrm{Mn}^{2+}$ to $\mathrm{Mn}^{3+}$

$(B)$ $\mathrm{O}_2$ oxidises both $\mathrm{Mn}^{2+}$ and $\mathrm{Fe}^{2+}$ to $\mathrm{Fe}^{3+}$

$(C)$ $\mathrm{Fe}^{3+}$ oxidizes $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$

$(D)$ $\mathrm{Mn}^{3+}$ oxidises $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$

$3.$ Sodium fusion extract, obtained from aniline, on treatment with iron $(II)$ sulphate and $\mathrm{H}_2 \mathrm{SO}_4$ in presence of air gives a Prussian blue precipitate. The blue colour is due to the formation of

$(A)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$ $(B)$ $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$

$(C)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$ $(D)$ $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$

Give the answer question $1,2$ and $3.$