$\mathrm{Ti}-3 d^{2} 4 s^{2} \rightarrow \mathrm{Ti}^{4+}-3 d^{0} 4 s^{0}$
$\mathrm{Cu}-3 d^{10} 4 s^{1} \rightarrow \mathrm{Cu}^{+}-3 d^{10} 4 s^{0}$
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$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{Conc.{H_2}S{O_4}}}}\limits_{Distillation} [X]$
$[X]$ will be :
$6 OH ^{-}+ Cl ^{-} \rightarrow ClO _{3}^{-}+3 H _{2} O +6 e ^{-}$
If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10\, g$ of $KCIO _{3}$ using a current of $2\, A$ is..........
(Given : $F =96,500\, C\, mol ^{-1}$ molar mass of $\left. KClO _{3}=122\,gmol ^{-1}\right)$
$NO\,\xrightarrow{{{O_2}}}A \rightleftharpoons D$
$A\xrightarrow{{NaOH\,\,(aq.)}}[B + C]$