Current $I$ is flowing along the path $ABCDA$ consisting of four edges of a cube (figure $-a$), produces a magnetic field $B_0$ at the centre of the cube. Find the magnetic field $B$ produced at the center of the cube by a current $I$ flowing along the path of the six edges $ABCGHEA$ (figure $b$)
Medium
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Imaging $3$ loops
$\mathrm{B}=\sqrt{\mathrm{B}_{0}^{2}+\mathrm{B}_{0}^{2}+\mathrm{B}_{0}^{2}}=\sqrt{3 \mathrm{B}}_{0}$ towards $\mathrm{F}$
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