CuSO_4 ⋅5H_2O is blue is colour while CuSO_4 is colourless due to… - Vidyadip

MCQ

$\ce{CuSO_4⋅5H_2O}$ is blue is colour while $\ce{CuSO_4}$ is colourless due to:

A
Presence of strong field ligand in $\ce{CuSO_4⋅5H_2O.}$
✓
Due to absence of water $($ligand$), d - d$ transitions are not possible in $\ce{CuSO_4.}$
C
Anhydrous undergoes $d - d$ transitions due to crystal field splitting.
D
Colour is lost due to unpaired electrons.

✓

Answer

Correct option: B.

Due to absence of water $($ligand$), d - d$ transitions are not possible in $\ce{CuSO_4.}$

In $\ce{CuSO_4.5H_2O,}$ water acts as ligand and causes crystal filed splitting. This makes $d - d$ transitions possible. On the other hand, in $\ce{CuSO_4,}$ due to absence of ligand crystal filed splitting is not possible.
Hence no colour is observed.

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