d dx (x e^ x^2 ) = - Vidyadip

MCQ

${d \over {dx}}(x{e^{{x^2}}}) = $

✓
$2{x^2}{e^x}^2 + {e^x}^2$
B
${x^2}{e^x}^2 + {e^x}^2$
C
${e^x}.2{x^2} + {e^x}^2$
D
None of these

✓

Answer

Correct option: A.

$2{x^2}{e^x}^2 + {e^x}^2$

a
(a) $\frac{d}{{dx}}\left( {x{e^{{x^2}}}} \right) = {e^{{x^2}}} + x{e^{{x^2}}}2x = {e^{{x^2}}}(1 + 2{x^2})$.

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