\(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}(\text { given })\)
When, \(I=5 m A, e^{1000 V / T}=6 m A\)
Also, \(d I=\left(e^{1000\, v / T}\right) \times \frac{1000}{T}\)
(By exponential function)
\(=(6\, m A) \times \frac{1000}{300} \times(0.01)\)
\(=0.2\, \mathrm{mA}\)