MCQ
$\Delta U^{\theta}$ of combustion of methane is $-X \,kJ \,mol ^{-1}.$  The value of $\Delta H^{\theta}$ is
  • A
    $=\Delta U^{\theta}$
  • $\,<\,\Delta U^{\theta}$
  • C
    $\,>\,\Delta U^{\theta}$
  • D
    $=0$

Answer

Correct option: B.
$\,<\,\Delta U^{\theta}$
b
Since $\Delta H^{\theta}=\Delta U^{\theta}+\Delta n_{g} R T$ and $\Delta U^{\theta}=-X \,k J\, mol ^{-1}$

$\Delta H^{\theta}=(-X)+\Delta n_{g} R T, \Rightarrow \Delta H^{\theta}\,<\,\Delta U^{\theta}$

Therefore, alternative $(ii)$ is correct.

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