Question
Derive the equation required for finding the activation energy.
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(Kf for water = 1.86 K kg mol–1)
| t/s | $10^{-2} \times\left[ N _2 O _5\right] / mol L ^{-1}$ |
| 0 | 1.63 |
| 400 | 1.36 |
| 800 | 1.14 |
| 1200 | 0.93 |
| 1600 | 0.78 |
| 2000 | 0.64 |
| 2400 | 0.53 |
| 2800 | 0.43 |
| 3200 | 0.35 |