Question
Describe an experiment to verify the Archimedes' principle.
✓
Answer
Let us take a solid and suspend it by a thin thread from the hook of a spring balance and note its weight. Then take a eureka can and fill it with water up to its spout. Arrange a measuring cylinder below the spout of the eureka can as shown. Immerse the solid gently in water. The water displaced by the solid gets collected in the measuring cylinder.
When water stops dripping through the spout, note the weight of the solid and volume of water collected in the measuring cylinder.
From diagram, it is clear that Loss in weight $($Weight in air $–$ weight in water$) = 300 \ gf\ – \ 200 \ gf = 100 \ gf$
Volume of water displaced $=$ Volume of solid $= 100 \ cm^3$
Because density of water $= 1 \ g\ cm^{-3}$
Weight of water displaced $= 100 \ gf =$ Upthrust or loss in weight This verifies Archimedes' principle.
When water stops dripping through the spout, note the weight of the solid and volume of water collected in the measuring cylinder.
From diagram, it is clear that Loss in weight $($Weight in air $–$ weight in water$) = 300 \ gf\ – \ 200 \ gf = 100 \ gf$
Volume of water displaced $=$ Volume of solid $= 100 \ cm^3$
Because density of water $= 1 \ g\ cm^{-3}$
Weight of water displaced $= 100 \ gf =$ Upthrust or loss in weight This verifies Archimedes' principle.
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