Question
Describe the manufacture of $H_2SO_4$ by contact process?

Answer

Preparation of sulphuric acid: By Contact Process: Burning of sulphur or sulphide ores in presence of oxygen to produce $SO_2.$ Catalytic oxidation of $SO_2$ with $O_2$ to give $SO_3$ in the presence of $V_2O_5.$
$2\text{SO}_2(\text{g})+\text{O}_2(\text{g})\xrightarrow[]{\text{v}_2\text{O}_5}2\text{SO}_3(\text{g})$
Then $SO_3$ made to react with sulphuric acid of suitable normality to obtain a thick oily liquid called oleum.
$\text{SO}_3(\text{g})+\text{H}_2\text{SO}_4(\text{l})\rightarrow\text{H}_2\text{S}_2\text{O}_7(\text{l})$
Then oleum is diluted to obtain sulphuric acid of desired concentration.
$\text{H}_2\text{S}_2\text{O}_7(\text{l})+\text{H}_2\text{O}(\text{l})\rightarrow2\text{H}_2\text{S}\text{O}_4(\text{l})$
The sulphuric acid obtained by contact process is $96 - 98\%$ pure.

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