$\because 0.1 \mathrm{mole}$

$X Y_{2} \equiv 10 g \therefore 1 \mathrm{mole}$

$X Y_{2} \equiv 100 g=X+2 Y=100 \ldots (1)$

For $X_{3} Y_{2}$

$\because 0.05$ mole

$X_{3} Y_{2}$

$\because 9 g$

$\therefore 1$ mole $X_{3} Y_{2} \equiv 180 g$

$3X+2Y=180\dots (2)$

On solving $(1)$ and $(2)$, $X=40$ And $Y=30$