Let $M=A^{13} B^{26}-B^{26} A^{13}$

Then, $M^T=\left(A^{13} B^{26}-B^{26} A^{13}\right)^{ T }$

$=\left(A^{13} B^{26}\right)^T-\left(B^{26} A^{13}\right)^{ T }$

$=\left(B^{ T }\right)^{26}\left(A^{ T }\right)^{13}-\left(A^{ T }\right)^{13}\left( B ^{ T }\right)^{26}$

$= B ^{26} A ^{13}- A ^{13} B ^{26}=- M$

Hence, $M$ is skew symmetric

Let, $N = A ^{26} C ^{13}- C ^{13} A ^{26}$

then, $N^{ T }=\left( A ^{26} C ^{13}\right)^{ T }-\left( C ^{13} A ^{26}\right)^{ T }$ $=-(C)^{13}(A)^{26}+A^{26} C^{13}=N$

Hence, $N$ is symmetric.

$\therefore$ Only $S2$ is true.