\(E _{2}=\phi+ K _{2}\) \(...(2)\)
\(E _{1}- E _{2}= K _{1}- K _{2}\)
Now \(\frac{ V _{1}}{ V _{2}}=2\)
\(\frac{ K _{1}}{ K _{2}}=4\)
\(K _{1}=4 K _{2}\)
Now from equation \((2)\)
\(\Rightarrow 4-2.5=4 K _{2}- K _{2}\)
\(1.5=3 K _{2}\)
\(K _{2}=0.5 eV\)
Now putting This
Value in equation \(( 2 )\)
\(2.5=\phi+0.5 eV\)
\(\phi=2 ev\)
(Assume $\mathrm{h}=6.63 \times 10^{-34} \mathrm{~J} \mathrm{~s}, \mathrm{~m}_{\mathrm{e}}=9.0 \times 10^{-31} \mathrm{~kg}$ અને $\mathrm{m}_{\mathrm{p}}=1836$ $x$ $\mathrm{m}_{\mathrm{e}}$ ધારો)