MCQ
Di-imide $(N_2H_4)$ is used to reduce doubble bond of
- A$ - \mathop C\limits_| = O$
- B$-C \equiv N$
- C$-NO_2$
- ✓$-CH =CH-$
✓
Answer
Correct option: D.
$-CH =CH-$
d
$(d)$ Di-imide is used to reduce pi-bond formed between like atom.
$(d)$ Di-imide is used to reduce pi-bond formed between like atom.
For example $\to -CH = CH-, - N = N -$
It can not be reduced following gps.
$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,N\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{ \to - C - , - C - , - N = O, - C \equiv N - NC,}
\end{array}$
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