MCQ
Dielectric constant of pure water is $81$. Its permittivity will be
- ✓$7.12 \times {10^{ - 10}}\,MKS$ units
- B$8.86 \times {10^{ - 12}}MKS$ units
- C$1.02 \times {10^{13}}\;MKS$ units
- DCannot be calculated
✓
Answer
Correct option: A.
$7.12 \times {10^{ - 10}}\,MKS$ units
a
(a) $\varepsilon = K{\varepsilon _0} = 81 \times 8.854 \times {10^{ - 12}}$$ = 7.17 \times {10^{ - 10}}\,MKS\,units$
(a) $\varepsilon = K{\varepsilon _0} = 81 \times 8.854 \times {10^{ - 12}}$$ = 7.17 \times {10^{ - 10}}\,MKS\,units$
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