From the dimensional consideration, which of the following equation is correct
A$T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
B$T = 2\pi \sqrt {\frac{{GM}}{{{R^3}}}} $
C$T = 2\pi \sqrt {\frac{{GM}}{{{R^2}}}} $
D$T = 2\pi \sqrt {\frac{{{R^2}}}{{GM}}} $
Medium
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A$T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
a (a) By substituting the dimensions in $T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
we get $\sqrt {\frac{{{L^3}}}{{{M^{ - 1}}{L^3}{T^{ - 2}} \times M}}} = T$
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