Question
Diethylamine to N-nitrosodiethylamine

Answer

$\begin{array}{lll}\left( C _2 H _5\right)_2 NH + HO - N = O & \xrightarrow[\text { cold }]{ NaNO _2+\text { dil. } HCl } & \left( C _2 H _5\right)_2 N - N = O + H _2 O \\ \text { Diethylamine } & & \text { N-Nitrosodiethylamine }\end{array}$

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