MCQ
Differential coefficient of ${\sin ^{ - 1}}{{1 - x} \over {1 + x}} \,\,,w.r.t$ $\sqrt x $ is
- A${1 \over {2\sqrt x }}$
- B${{\sqrt x } \over {\sqrt {1 - x} }}$
- C$1$
- ✓None of these
==>$\frac{{dy}}{{dx}} = \frac{{ - 1}}{{\sqrt x (1 + x)}}$ ....$(i)$
and $z = \sqrt x $==>$\frac{{dz}}{{dx}} = \frac{1}{{2\sqrt x }}$ .....$(ii)$
Therefore by $(i)$ and $(ii)$
$\frac{{dy}}{{dz}} = \frac{{dy/dx}}{{dz/dx}} = \frac{{ - 2}}{{1 + x}}$.
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