MCQ
Dilute nitric acid on reaction with silver liberates
- ✓$NO$ gas
- B$NO_2$ gas
- C$N_2$ gas
- D$O_2$ gas
$3 Ag +4 HNO _3(\text { dil }) \rightarrow 3 AgNO _3+2 H _2 O + NO \uparrow$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$

