Question
Dipole moment in case of $BeF2$ is zero. Explain.
✓
Answer
Dipole moment is a vector quantity. Therefore, the resultant dipole moment of a molecule is the vector sum of dipole moments of various bonds in the molecule.
In $BeF_2$ molecule$, Be-F$ bond is polar and has a bond dipole moment.
$BeF_2$ is a linear molecule with two $Be-F$ bonds oriented at $180^\circ ($opposite to each other$).$
The two bond dipoles are equal in magnitude and act in opposite direction to cancel each other. Therefore, the net dipole moment in case of $BeF_2$ is zero.
In $BeF_2$ molecule$, Be-F$ bond is polar and has a bond dipole moment.
$BeF_2$ is a linear molecule with two $Be-F$ bonds oriented at $180^\circ ($opposite to each other$).$
The two bond dipoles are equal in magnitude and act in opposite direction to cancel each other. Therefore, the net dipole moment in case of $BeF_2$ is zero.
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