Displacement versus time curve for a particle executing S.H.M. is… - Vidyadip

Question

Displacement versus time curve for a particle executing $\text{S.H.M}$. is shown in Fig. Identify the points marked at which,

Velocity of the oscillator is zero,
Speed of the oscillator is maximum.

✓

Answer

Key concept: In displacement$-$time graph of $\text{SHM}$, zero displacement values correspond to mean position; where velocity of the oscillator is maximum. Whereas the crest and troughs represent amplitude positions, where displacement is maximum and velocity of the oscillator is zero.

The points $\text{A, C, E, G}$ lie at extreme positions $($maximum displacement, $y = A).$ Hence the velocity of the oscillator is zero.
The points $\text{B, D, F, H}$ lie at mean position $($zero displacement, $y = 0)$. We know the speed is maximum at mean position.

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