Question
$\frac{d}{{dx}}\log \tan \left( {\frac{\pi }{4} + \frac{x}{2}} \right) = $
$ = \frac{1}{2}.\frac{1}{{\sin \left( {\frac{\pi }{4} + \frac{x}{2}} \right)\cos \left( {\frac{\pi }{4} + \frac{x}{2}} \right)}} = \frac{1}{{\sin \left( {\frac{\pi }{2} + x} \right)}} = \frac{1}{{\cos x}} = \sec x$.
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