MCQ
$\frac{{dy}}{{dx}} = {2^{y - x}}$ નો ઉકેલ મેળવો.
- A${2^x} + {2^y} = c$
- B${2^x} - {2^y} = c$
- ✓$\frac{1}{{{2^x}}} - \frac{1}{{{2^y}}} = c$
- D$x + y = c$
Integrating both sides, $\int {\frac{{dy}}{{{2^y}}} = \int {\frac{{dx}}{{{2^x}}}} } $
$ - {2^{ - y}}\log 2 = - {2^{ - x}}\log 2 + {c_1}$
$\frac{{\log 2}}{{{2^x}}} - \frac{{\log 2}}{{{2^y}}} = {c_1}$; $\frac{1}{{{2^x}}} - \frac{1}{{{2^y}}} = \frac{{{c_1}}}{{\log 2}} = c$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.