3A - ( 2 - A ) A + ( + 3A) = - Vidyadip

MCQ

$\frac{{\sin 3A - \cos \left( {\frac{\pi }{2} - A} \right)}}{{\cos A + \cos (\pi + 3A)}} = $

A
$\tan A$
B
$\cot A$
C
$\tan 2A$
✓
$\cot 2A$

✓

Answer

Correct option: D.

$\cot 2A$

d
(d) $\frac{{\sin 3A - \cos \left( {\frac{\pi }{2} - A} \right)}}{{\cos A + \cos (\pi + 3A)}}$

$ = \frac{{\sin 3A - \sin A}}{{\cos A - \cos 3A}}$

$=\frac{{2\cos 2A\sin A}}{{2\sin 2A\sin A}}$

$= \frac{{\cos 2A}}{{\sin 2A}} = \cot 2A$.

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