MCQ
$\frac{{\sin 3A - \cos \left( {\frac{\pi }{2} - A} \right)}}{{\cos A + \cos (\pi + 3A)}} = $
- A$\tan A$
- B$\cot A$
- C$\tan 2A$
- ✓$\cot 2A$
$ = \frac{{\sin 3A - \sin A}}{{\cos A - \cos 3A}}$
$=\frac{{2\cos 2A\sin A}}{{2\sin 2A\sin A}}$
$= \frac{{\cos 2A}}{{\sin 2A}} = \cot 2A$.
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