Question
Factorize of the following algebraic expression: $4(x + y)(3a - b) + 6(x + y)(2b - 3a)$
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Answer
$4(x + y)(3a - b) + 6(x + y)(2b - 3a)$
$= 2(x + y) [2(3a - b) + 3(2b - b)] [$taking $(2(x + y))$ as the common factor$] $
$= 2(x + y)(6a - 2b + 6b - 9a) = 2(x - y)(4b - 3a)$
$= 2(x + y) [2(3a - b) + 3(2b - b)] [$taking $(2(x + y))$ as the common factor$] $
$= 2(x + y)(6a - 2b + 6b - 9a) = 2(x - y)(4b - 3a)$
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