d
(d) \({v_{\max }} = a\omega = \frac{v}{{10}} = \frac{{10}}{{10}} = m/sec\)
\( \Rightarrow \)\(a\omega = a \times 2\pi n = 1\)\( \Rightarrow \)\(n = \frac{{{{10}^3}}}{{2\pi }}\)                        \((\because a=10^{-3})\)
Since \(v = n\lambda \Rightarrow \lambda = \frac{v}{n} = \frac{{10}}{{{{10}^3}/2\pi }} = 2\pi \times {10^{ - 2}}\,m\)