\(y=0.002 \sin (300 t-15 x)\)
From the above equation,
\(\omega=300\)
\(k=15\)
The wave speed is calculated as,
\(v=\frac{\omega}{k}\)
\(=\frac{300}{15}\)
\(=20 m / s\)
Also, the expression for the wave speed in the string is,
\(v=\sqrt{\frac{T}{\mu}}\)
\(20=\sqrt{\frac{T}{0.1}}\)
\(T=0.1 \times 20^{2}\)
\(=40 N\)