Question
Draw formulas for the first five members of homologous series beginning with the following compounds.
$\mathrm{H}-\mathrm{CH}=\mathrm{CH}_2$.
$\mathrm{H}-\mathrm{CH}=\mathrm{CH}_2$.
✓
Answer
The first five members of each homologous series beginning with the given compounds are shown as follows:
$\mathrm{H}-\mathrm{CH}=\mathrm{CH}_2$ : Ethene
$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$ : Propene
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2$ : 1-Butene
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2$ : 1-Pentene
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2:$ 1-Hexene.
$\mathrm{H}-\mathrm{CH}=\mathrm{CH}_2$ : Ethene
$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$ : Propene
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2$ : 1-Butene
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2$ : 1-Pentene
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2:$ 1-Hexene.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Why do real gases deviate from the ideal behaviour? What are the conditions under which real gases show ideal behaviour?
Why does hydrogen occur in a diatomic form rather than in a monoatomic form under normal conditions?
In an atom, an electron is moving with a speed of $600 \mathrm{~ms}^{-1}$ with an accuracy of $0.005 \%$. Find the certainty with which the position of the electron can be located. $\left(\mathrm{h}=6.6 \times 10^{-34} \mathrm{~kg} / \mathrm{m}^2 \mathrm{~s}^{-1}\right.$, mass of electron $\left.\mathrm{me}=9.1 \times 10^{-31} \mathrm{~kg}\right)$.
→Calculate the mass percent of calcium, phosphorus and oxygen in calcium phosphate $\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2$.
→Give reason for the following statements.
- Halogens act as good oxidising agents.
- Electron gain enthalpy of noble gases is almost zero.
Write IUPAC name of following compounds :
Calculate the wavelength of one photon whose energy is 1 eV .
In a reaction
$\mathrm{A}+\mathrm{B}_2 \rightarrow \mathrm{AB}_2$
Identify the limiting reagent, if any, in the following reaction mixtures. $2 \mathrm{~mol} \mathrm{~A}+3 \mathrm{~mol} \mathrm{~B}$.
→$\mathrm{A}+\mathrm{B}_2 \rightarrow \mathrm{AB}_2$
Identify the limiting reagent, if any, in the following reaction mixtures. $2 \mathrm{~mol} \mathrm{~A}+3 \mathrm{~mol} \mathrm{~B}$.
In Rutherford’s experiment, generally the thin foil of heavy atoms, like gold, platinum etc. have been used to be bombarded by the $\alpha$-particles. If the thin foil of light atoms like aluminium etc. is used, what difference would be observed from the above results?
→The combustion of benzene(I) gives $\mathrm{CO}_2(\mathrm{g})$ and $\mathrm{H}_2 \mathrm{O}(\mathrm{I})$. Given that heat of combustion at constant volume is $-3263.9 \mathrm{~kJ} \mathrm{~mol}^{-1}$ at $25^{\circ} \mathrm{C}$; calculate heat of combustion in $\mathrm{kJ} \mathrm{~mol}{ }^{-1}$ at constant pressure. $\left[\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right]$
→