- A$16$
- B$20$
- ✓$22$
- D$18$
Atomic no. of $Fe =26$
Oxidation no. of Fe in the given compound is $=3$
Coordination no. $=6$
E.A.N. $=26-3+2 \times 6=35$.
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Assertion $A :$ Flourine forms one oxoacid.
Reason $R$ : Flourine has smallest size amongst all halogens and is highly electronegative
In the light of the above statements, choose the most appropriate answer from the options given below.

$(i) \,\,\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH - C{H_3}} \\
{\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}\,\xrightarrow{{{H^ + }/heat}}\,\,\mathop A\limits_{[Major\,product]} \, + \,\mathop B\limits_{[Minor\,product]} $
$(ii)\,\, A\xrightarrow[{in\,\,absence\,\,\,of\,peroxide}]{{HBr,\,dark}}\,\,\mathop C\limits_{[Major\,product]} \, + \,\mathop D\limits_{[Minor\,product]} $
the major products $(A)$ and $(C)$ are respectively
