Eight resistances each of resistance $5\,\Omega $ are connected in the circuit as shown in figure. The equivalent resistance between $A$ and $B$ is
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$R^{\prime}=\frac{2 R^{2}}{3 R}$
$R^{\prime}=\frac{2 R}{3}$
$R^{\prime}=\frac{2 R}{3}+2 R$
$R^{\prime}=\frac{8 R}{3}$
$R_{e q}=\frac{2 R \cdot R \cdot 8 R / 3}{2 R^{2}+16 R^{2} / 3+8 R^{2} / 3}$
$R_{eq}=\frac{16 R^{3} / 3}{10 R^{2}}$
$R_{e q}=\frac{8 R}{15}$
$=\frac{8 \times 5}{15}=\frac{8}{3} \Omega$
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