\(h = 0 + \frac{1}{2}(9.8){(2)^2} = 19.6\,m\)
\(\frac{{\Delta h}}{h} = \pm 2\left( {\frac{{\Delta t}}{t}} \right)\) \((\because {a = g}\) અચળ\()\)
\( = \pm 2\left( {\frac{{0.1}}{2}} \right) = \pm 0.1\,\)
\(\therefore \Delta h= \pm \frac{h}{{10}} = \pm \frac{{19.6}}{{10}}= \pm 1.96\,m\)