at given point
\(\mathrm{KE}=3 \mathrm{PE}\)
So, \(4 \mathrm{PE}=\mathrm{mgs}\)
\(4 \mathrm{mgh}=\mathrm{mgs}\)
\(\mathrm{H}=\mathrm{s} / 4\)
\(\mathrm{KE}=\frac{3 \mathrm{mgs}}{4}=\frac{1}{2} \mathrm{mV}^{2}\)
\(\mathrm{~V}=\sqrt{\frac{3\times 2 \mathrm{gs}}{4}}=\sqrt{\frac{3 \mathrm{gS}}{2}}\)