\(v=\frac{t^2}{10}+20\)
To find acceleration find \(\frac{d v}{d t}\)
So, \(a=\frac{d v}{d t}=\frac{2 t}{10}+0\)
\(\Rightarrow a=\frac{t}{5} \Rightarrow a \propto t\)
\(\because a\) is a function of time so it is not constant, rather it is non-uniform.