c
(c) if body is projected with velocity \(\mathrm{V}\left(\mathrm{V}<\mathrm{V}_{\mathrm{e}}\right)\) then height upto where it rises

\(\mathrm{h}=\left[\mathrm{R} /\left\{\left(\mathrm{V}_{\mathrm{e}}^{2} / \mathrm{V}^{2}\right)-1\right\}\right]\)

\(=\left[\mathrm{R} /\left\{(11.2 / 10)^{2}-1\right\}\right]……………….\mathrm{V}_{\mathrm{e}}=11.2 \mathrm{km} / \mathrm{s}\)

\(\mathrm{h}=3.93 \mathrm{R}\)

\(h \approx 4 R\)