There is no acceleration in the horizontal direction.

\(S_x=U_x T+\frac{1}{2} a_0 \times T^2\)

\(R=U_x T \ldots (1)\)

\(S_y=U_y T+\frac{1}{2} g_y T^2\)

\(O=V_1 T-\frac{1}{2} g T^2\)

\(\Rightarrow V_1 T=\frac{1}{2} g T\)

\(T=\frac{2 V_1}{g}\)

We know,

\((R)\) range \(=(\) Horizontal velocity \(4 x) \times\) flight \(+\) time \((T)\)

i.e., \(R=4 x \times T\)

\(R=V_2 \times \frac{2 V_1}{g} \Rightarrow \frac{2 V_1 V_2}{g}\)