Weight of metal $= 100\,g - 74.75\,g$

                          $= 25.25\,g$

Equivalent weight

$ = \frac{{weight\,of\,metal}}{{weight\,of\,chlorine\,}} \times 35.5$

$ = \frac{{25.25}}{{74.75}} \times 35.5 = 12$

Valency of metal

$ = \frac{{2 \times V.D.}}{{Equivalent\,wt.of\,metal + 35.5}}$

$ = \frac{{2 \times 94.8}}{{12 + 35.5}} = 4$

$\therefore $ Formula of compound $= MCl_4$